0=t^2/24+0.25t-4.6

Solution for 0=t^2/24+0.25t-4.6 equation:

0=t^2/24+0.25t-4.6

We move all terms to the left:

0-(t^2/24+0.25t-4.6)=0


Domain of the equation: 24+0.25t-4.6)!=0

We move all terms containing t to the left, all other terms to the right

0.25t-4.6)!=-24

t∈R


We add all the numbers together, and all the variables

-(t^2/24+0.25t-4.6)=0

We get rid of parentheses

-t^2/24-0.25t+4.6=0

We multiply all the terms by the denominator


-t^2-(0.25t)*24+(4.6)*24=0

We add all the numbers together, and all the variables

-t^2-(+0.25t)*24+(4.6)*24=0

We add all the numbers together, and all the variables

-1t^2-(+0.25t)*24+110.4=0

We multiply parentheses

-1t^2-0t+110.4=0

We add all the numbers together, and all the variables

-1t^2-1t+110.4=0

a = -1; b = -1; c = +110.4;
Δ = b2-4ac
Δ = -12-4·(-1)·110.4
Δ = 442.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{442.6}}{2*-1}=\frac{1-\sqrt{442.6}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{442.6}}{2*-1}=\frac{1+\sqrt{442.6}}{-2}
$